By definition, the area of the square is given by:
[tex] A = L ^ 2 [/tex]
Where,
L: length of the sides of the square
Substituting values we have:
[tex] L^2 = 81 [/tex]
From here, we clear the length of the sides:
[tex] L = \sqrt{81} [/tex]
[tex] L = 9 [/tex]
Then, the perimeter of the square is given by:
[tex] P = 4L [/tex]
Substituting values we have:
[tex] P = 4 (9) [/tex]
[tex] P = 36 [/tex]
Answer:
The perimeter of the frame is:
[tex] P = 36 [/tex]
