fliptastic09 fliptastic09
  • 03-05-2019
  • Mathematics
contestada

The equation v(x)=32500(0.92)^x how much more is the truck worth after two years than after three years

Respuesta :

altavistard
altavistard altavistard
  • 06-05-2019

Answer:

the difference:  $2,192.64

Step-by-step explanation:

After 1 year, the truck has lost 8% of its value:  v(x) = $32,500(0.92)^1, or

$29,900.

After 2 years, v(x) = $32,500(0.92)^2, or $27,500.  Finally, after 3 years,

v(x) = $32,500(0.92)^3 = $25,307.36.

Subtracting $25,307.36 (the value after 3 years) from $27,500 (the value after 2 years) yields the difference:  $2,192.64

Answer Link

Otras preguntas

Find the product of 2(5.9) mentally using the distributive property.
What was the goal of farm labor movement
Please really need help on this thanks
What are three aspects of Peruvian culture that are different from the United States?
(02.06)How many pounds are there in 2 and 3 over 4 tons? (1 ton = 2000 pounds)
6a−3b=5b solve for a:b ratio plz help
rephrase this for 80-90 points The Seafarer  The Seafarer is the main hero of the Anglo-Saxon ballad. The character has embraced willful by picking an existence
"22 POINTS PLEASE ANSWER" What was the Roman Pontifex? A. a papal decree that gave Portugal control over trade in the Americas B. a papal decree that gave
15 computers for 45 students, 45 computers for 135 students
Isotope of an element differ in their