ZJSG09112007
ZJSG09112007 ZJSG09112007
  • 01-12-2020
  • Mathematics
contestada

Hi. I need help with these questions.
See image for question.
No jokes
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Hi I need help with these questionsSee image for questionNo jokes class=

Respuesta :

mhanifa
mhanifa mhanifa
  • 01-12-2020

Step-by-step explanation:

Given

  • P(x) = 6x³ + 4x² - x + 5

Divide by the following:

(a) 3x² + 2x + 1

  • 6x³ + 4x² - x + 5 =
  • 2x(3x²) + 2x(2x) + 2x - 3x + 5 =
  • 2x(3x² + 2x + 1) + (-3x + 5)

Quotient = 2x, remainder = -3x + 5

(b) x³ - 3x + 2

  • 6x³ + 4x² - x + 5 =
  • 6(x³) - 6(3x) + 6(2) + 4x² + 22x - 7
  • 6( x³ - 3x + 2) + (4x² + 22x - 7)

Quotient  = 6, remainder  = 4x² + 22x - 7

(c) 6x² + x - 2

  • 6x³ + 4x² - x + 5 =
  • x(6x²) + x(x) - x(2) + 3x² + x + 5 =
  • x(6x² + x - 2) + (3x² + x + 5)

Quotient  = x, remainder = 3x² + x + 5

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