Simplytaylorgrenade
Simplytaylorgrenade Simplytaylorgrenade
  • 01-11-2016
  • Chemistry
contestada

Which is the acceleration of a 32-kg object if a 6.75-N force is applied to it?

A 216.00 m/s2
B.21.09 m/s2
C. 4.74 m/s2
D. 0.21 m/s2

Respuesta :

dreamzyusmania
dreamzyusmania dreamzyusmania
  • 01-11-2016
F=ma F/m=a 6.75/32=0.21m/s2 means d is your right answer!
Answer Link
Dejanras
Dejanras Dejanras
  • 04-11-2018

Аnswer is: the acceleration is D. 0.21 m/s².

Newton's second law of motion: F = m · a.

F -  force applied.

m - mass of the object receiving the force.

a - the acceleration of the object.

a = F ÷ m.

a = 6.75 N ÷ 32 kg.

a = 0.21 m/s².

One newton is the force needed to accelerate one kilogram of mass at the rate of one metre per second squared in direction of the applied force.

Answer Link

Otras preguntas

I need a Amazon tribe name please! Need for Monday
after clicking the start button on your computer screen desktop what option would you then select to examine system components you might want to modify?
solve for x: 2x^2+4x-16+=0
how do i round 3,176 to the nearest thousand
Which substance will combine with oxygen gas to produce a greenhouse gas? a. Na b. S c. H₂ d. Ne e. C
do you know how to say my in Spanish?
what does the zeppelin
Many colonial people volunteered to fight for the Allied forces because they hoped their service would win their colony's ____
How can b^2+9b+14 be re-written?1) (b+7) (b-7)2) (b-7) (b-2)3) (b+7) (b-2)4) (b+7) (b+2)
which expression is equivalent to x^4-y^4?