Answer:
Step-by-step explanation:
The zeros of the function can be found by factoring. Since this has already been started with completing the square, we will just pick up from where it was left and finish factoring. Set the quadratic equal to 0 first.
[tex](x-8)^2-9=0[/tex] then move over the 9:
[tex](x-8)^2=9[/tex] "undo" the squaring by square rooting both sides to get
x - 8 = ±3. And then add over the 8 to get the solutions
x = 8 + 3 and x = 8 - 3. The solutions, then, are
x = 5 and x = 11
