melissa1274
melissa1274 melissa1274
  • 05-08-2021
  • Mathematics
contestada

Find the equation of the tangent line at the point (0,1) of the graph of the function f(x) = x^3 - 2x + 1 ?​

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 09-08-2021

9514 1404 393

Answer:

  y = -2x +1

Step-by-step explanation:

The derivative of the function is ...

  f'(x) = 3x^2 -2

so the slope at x=0 is f'(0) = -2. In slope-intercept form, the equation of the tangent line is ...

  y = -2x +1

Ver imagen sqdancefan
Answer Link

Otras preguntas

No question………………………
PLZ I NEED THIS ASAP!!! ILL GIVE YOU BRAINLIST!!!!
Can anyone help? Thanks
There is an investigation with the two variables below. Identify the Independent variable. * A. Amount of water given to bean plants (mL) B. How tall the bean p
What was the Declaration of Independence for Thomas Jefferson and the committee of five
You want to have an equal number of 5 noisemakers and 30 balloons at your party.What is the least number of packs of each you can buy?
Jason hands the cashier $10.00. How much change should he get back
Hi, so I'm having trouble remembering what a explanatory model and a feedback loop is Can anyone jog up my memory? I got a project due tomorrow and I need those
भोजपत्र एक प्रकारको लेकाली जातको रुखको ...... हो ।​
help me please...........​