if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?

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02-02-2017
Physics

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if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?

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marklukomskiy marklukomskiy · Answer 1 · 2017-02-02T21:38:19+01:00

marklukomskiy marklukomskiy

02-02-2017

I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
So the centripetal force is divided by 4.

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ashirashfaq ashirashfaq · Answer 2 · 2017-02-02T21:39:36+01:00

ashirashfaq ashirashfaq

02-02-2017

it should be the 4... so the answer is 4...

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