Respuesta :

bharathparasad577

Given:

  • V=0.280 L.
  • Mass of the gas=0.400g.
  • Temperature=273K
  • PV=nRT
  • n=PV/RT

         =1*0.280 L/0.0821*273

         =0.0124moles.

  • Molar mass of the gas=Mass of the gas/n

                                          =0.400/0.0124=32.26g

Therefore, molar mass of the gas is approximately 32.26g.

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