JeremeyD675672 JeremeyD675672

03-11-2022
Physics

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A 5.0n force is applied to a 3.0kg ball to change its velocity from +9.”m/s to +3.0 m/s. The impulse on the ball is _I think it’s -18

Respuesta :

KeniyaA559940 KeniyaA559940

03-11-2022

Given,

The force is F=5 N.

The mass is m=3.0 kg

The velocities are 9 m/s to 3 m/s

The impulse is:

[tex]\begin{gathered} I=m(v_f-v_i) \\ \Rightarrow I=3(9-3) \\ \Rightarrow I=\frac{18kgm}{s} \end{gathered}[/tex]

The answer is 18 kgm/s

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