Respuesta :

mreijepatmat
f(x)=6x²-6x+128

1) This parabola has a maximum (open down) since the coefficient of x² (that is 6) is positive.

2) It doesn't intercepts the x-axis since its roots are imaginary :
    x' =4.292 i  & x" = -4.592 i 

3) its axis of symmetry = -b/2a = 1/2 ===> x= 1/2


The tan at the minimum ===> dy/dx = 12x-6  ===>(x=1/2), dy/dx =0

This parabola is decreasing in the interval ]x=-∞, 0[ ∪ ]0, ∞[

minimum (1/2, 126.5)

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